4.9x^2+27x-13=0

Solution for 4.9x^2+27x-13=0 equation:

4.9x^2+27x-13=0

a = 4.9; b = 27; c = -13;
Δ = b2-4ac
Δ = 272-4·4.9·(-13)
Δ = 983.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{983.8}}{2*4.9}=\frac{-27-\sqrt{983.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{983.8}}{2*4.9}=\frac{-27+\sqrt{983.8}}{9.8}
$